{{ชื่อ}} ประเภทบุคลิกภาพ MBTI
บุคลิกภาพ
"Zoé Lee “Vesperia” ประเภทบุคลิกภาพประเภทใด Zoé Lee “Vesperia” เป็นประเภทบุคลิกภาพ INFJ ใน mbti, 9w1 - so/sp - 926 ใน Enneagram, RCOAI ใน Big 5, SEI ใน Socionics"
I think she is an INFJ. Unlike her older sister, she is a kind and caring cute girl. Her kind and good-natured nature puts on a fake appearance to impress her family. She worked to be recognized, to be loved, which I felt was consistent with 2w3's look to be loved. 2 to 3 wings add adaptability. When she first met Marinette, she won her liking for her closeness and charming behavior. INFJs with 2w3 are charming and friendly. 2w3s love the attention of others and have conversational skills that give others warmth. Like this, she felt like acting like a 2w3. She acted like a selfish child to gain recognition. But even when she did, she didn't get the attention. She thinks about what kind of action is more right and right. Preferring to be loved and well-behaved by her friends rather than acting for the approval of her sister, she therefore chose her friends over her family, realizing that it was better to be with her friends than to act. The Fe function adopts a behavior appropriate to the situation. Seeing her act according to her situation, I felt her Ni function kicking in. She weighs "what feels certain" in her own judgment. She thinks that Ni features are revealed a lot. In the inner conflicts among her friends and family, she ponders what is right and certain with the Ni+Fe function. Here, she thinks 'I' with the Ti function what feels right. I can't write it perfectly because the knowledge in my head is not organized. So, this article is my personal opinion. I'm thinking she's her INFJ 2w3 (2w3, 6w5, 9w1). - 나는 그녀가 INFJ라고 생각합니다. 그녀는 언니와는 반대로 친절하고 남을 생각해주는 귀여운 여자아이입니다. 친절하고 착한 그녀는 가족들에게 잘 보이기 위해 거짓된 모습을 연기하며 지내게 됩니다. 인정받기 위해, 사랑받기 위해 노력했습니다, 이러한 면은 2w3의 사랑받기 위한 모습과 일치한다고 느꼈습니다. 2번에 3번 날개는 적응력을 더해줍니다. 처음에 마리네뜨와 만났을때 친밀감과 매력적인 행동으로 호감을 얻었습니다. 2w3을 가진 INFJ는 매력적이고 친근합니다. 2w3은 다른 사람의 관심을 좋아하고 다른 사람에게 따뜻함을 주는 대화 능력을 가지고 있습니다. 이처럼 그녀는 2w3과 같이 행동한다고 느꼈습니다. INFJ인 이유를 설명하겠습니다. 그녀는 인정받기 위해 이기적인 아이처럼 행동했습니다. 하지만 그렇게해도 관심을 받지 못하였습니다. 그녀는 더 맞고 옳은게 어떤행동인지 고민합니다. 언니에게 인정받기 위해 행동하는것보다 친구들에게 사랑을 받으며 잘 지내는것을 선호했던 그녀는 따라서 행동하는것보다 친구들과 함께 지내는게 좋다는걸 깨달아서 가족보다 친구를 선택하게 되었습니다. Fe 기능은 상황에 적합한 행동양식을 취합니다. 상황에 맞게 행동하는 그녀를 보고 Ni기능이 발동한다고 느꼈습니다. 그녀는 자신의 판단으로 "무엇이 확실하다고 느끼는가"를 따집니다. Ni 기능이 많이 드러났다고 생각합니다. 친구들과 가족들 사이에서의 내적 갈등에서 그녀는 Ni + Fe 기능으로 무엇이 옳고 확실한지를 깊게 생각합니다. 여기서 Ti 기능으로 '나는' 무엇이 맞다고 느끼는가를 생각합니다. 제가 머리속에 있는 지식들이 정리가 안되서 완벽하게 작성할 수 없습니다. 그렇기에 이 글은 제 개인적인 의견입니다. 저는 그녀가 INFJ 2w3 (2w3, 6w5, 9w1)이라고 생각을 하고 있습니다.
ชีวประวัติ
Zoé Lee is a supporting character in Miraculous: Tales of Ladybug & Cat Noir . She is a teenage girl from New York City and a student in Ms. Mendeleiev's class at Collège Françoise Dupont. She is also Chloé Bourgeois's younger half-sister and André Bourgeois's stepdaughter. She attended a boarding school when she was in New York, where she once lived with her mother. In "Sole Crusher", after being tired of hiding her true self in order to please her half-sister, Zoé is akumatized by Shadow Moth into Sole Crusher, a supervillain who can absorb people and becomes larger by stomping on or kicking them. She also receives a Magical Charm from Ladybug that prevents her from being akumatized again.
บุคลิกภาพ correlate
Adrien Agreste “Chat Noir”
Marinette Dupain-Cheng “Ladybug”
Lila Rossi
Plagg
Félix Fathom "Argos"
Luka Couffaine "Viperion"
Chloé Bourgeois “Queen Bee“
Alya Césaire "Rena Rouge"
